(2v-6)/(v^2-2v-3)

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Solution for (2v-6)/(v^2-2v-3) equation: 


D( v )

v^2-(2*v)-3 = 0

v^2-(2*v)-3 = 0

v^2-(2*v)-3 = 0

v^2-2*v-3 = 0

v^2-2*v-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

v = (16^(1/2)+2)/(1*2) or v = (2-16^(1/2))/(1*2)

v = 3 or v = -1

v in (-oo:-1) U (-1:3) U (3:+oo)

(2*v-6)/(v^2-(2*v)-3) = 0

(2*v-6)/(v^2-2*v-3) = 0

v^2-2*v-3 = 0

v^2-2*v-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

v = (16^(1/2)+2)/(1*2) or v = (2-16^(1/2))/(1*2)

v = 3 or v = -1

(v+1)*(v-3) = 0

(2*v-6)/((v+1)*(v-3)) = 0

2*v-6 = 0 // + 6

2*v = 6 // : 2

v = 6/2

v = 3

v in { 3} 

v belongs to the empty set

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